write-up: Hardware/Signal_Tap_Lain/README.md

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# Signal Tap Lain — Solution
# Signal Tap Lain
## Overview
| Field | Value |
|-------|-------|
| Category | Hardware |
| Difficulty | Medium-Hard |
| Points | 500 |
| Author | Eun0us |
| CTF | Espilon 2026 |
A logic analyzer capture is streamed with 3 channels. Channel 1 (ch1) contains
UART data at 9600 baud, 8N1 format. The player must identify the protocol from
signal timing and decode the ASCII message.
---
## Steps
## Description
1. Connect and capture the data:
A debug probe is capturing signals from Lain's NAVI.
Three channels are being recorded, but what protocol is in use?
- Signal Tap: `tcp/<host>:3800`
Capture the data, identify the protocol, and decode the message.
Format: **ESPILON{...}**
---
## TL;DR
Download a multi-channel logic analyzer CSV capture. Identify that channel 1 carries UART
at 9600 baud by measuring the bit period. Implement UART 8N1 decoding (LSB-first) and
extract the ASCII flag, which is repeated 3 times in the stream.
---
## Tools
| Tool | Purpose |
|------|---------|
| `nc` | Capture the signal tap data |
| Python 3 / numpy | Logic analysis and UART decoding |
| `info` command | Get channel metadata from the service |
---
## Solution
### Step 1 — Connect and capture
```bash
nc <host> 3800 > capture.csv
```
Wait for `--- END OF CAPTURE ---`.
Wait for `--- END OF CAPTURE ---` then press Ctrl+C.
1. Analyze the capture. Use `info` command for metadata:
### Step 2 — Get metadata
Connect again and issue:
```text
info
```
Shows 3 channels: ch0 (reference), ch1 (data), ch2 (noise).
Output:
1. Focus on ch1. Look for patterns:
```
Channels: 3
ch0: reference clock (always HIGH)
ch1: data line
ch2: noise channel
Sample rate: 1 MHz
```
- Idle state is HIGH (1)
- Periodic falling edges = start bits
- Measure time between start bits to find character period
> 📸 `[screenshot: info command output listing the three channels]`
1. Calculate baud rate:
### Step 3 — Analyze channel 1
- Bit period ≈ 104.17 μs → 9600 baud
- Character frame = 10 bits (1 start + 8 data + 1 stop) = ~1041.67 μs
Focus on ch1. The key observations:
1. Decode UART 8N1:
- Idle state is **HIGH** (logic 1) — consistent with UART
- Periodic **falling edges** = start bits
- Measure the time between the start bit falling edge and the next bit transition
- Start bit: falling edge (HIGH → LOW)
- Sample data bits at center of each bit period (1.5 × bit_period after start)
- 8 data bits, LSB first
- Stop bit: HIGH
### Step 4 — Calculate baud rate
1. Script or manually decode the ch1 data to ASCII. The message contains the flag
repeated 3 times.
Measure the minimum pulse width in the ch1 column:
## Key Concepts
```
Bit period ≈ 104.17 μs
Baud rate = 1 / 0.00010417 ≈ 9600 baud
```
- **Logic analysis**: Reading digital signals and identifying protocols from timing patterns
- **UART 8N1**: Universal Asynchronous Receiver/Transmitter — start bit, 8 data bits LSB-first, no parity, 1 stop bit
- **Baud rate detection**: Measuring the shortest pulse width gives the bit period → baud rate
- **Signal separation**: In a multi-channel capture, identifying which channel carries useful data
A 10-bit UART frame (1 start + 8 data + 1 stop) = ~1041.67 μs.
> 📸 `[screenshot: Python script measuring bit periods from ch1 transitions]`
### Step 5 — Decode UART 8N1
```python
import csv
# Load capture
with open("capture.csv") as f:
reader = csv.DictReader(f)
rows = list(reader)
timestamps = [float(r["timestamp_us"]) for r in rows]
ch1 = [int(r["ch1"]) for r in rows]
BIT_PERIOD = 104.17 # microseconds at 9600 baud
chars = []
i = 0
while i < len(ch1) - 1:
# Find start bit (falling edge: HIGH → LOW)
if ch1[i] == 1 and ch1[i+1] == 0:
start_time = timestamps[i+1]
# Sample 8 data bits at center of each bit period
bits = []
for b in range(8):
sample_time = start_time + BIT_PERIOD * (1.5 + b)
# Find closest sample
j = min(range(len(timestamps)),
key=lambda k: abs(timestamps[k] - sample_time))
bits.append(ch1[j])
# LSB first
byte = int("".join(map(str, reversed(bits))), 2)
if 32 <= byte <= 126:
chars.append(chr(byte))
i += int(BIT_PERIOD * 10 / (timestamps[1] - timestamps[0]))
else:
i += 1
print("".join(chars))
```
The decoded message contains the flag repeated three times.
> 📸 `[screenshot: decoded UART output showing the flag repeated]`
### Key concepts
- **Logic analysis**: Reading digital waveforms and identifying protocols from timing patterns
- **UART 8N1**: Start bit (HIGH→LOW), 8 data bits LSB-first, no parity bit, 1 stop bit (HIGH)
- **Baud rate detection**: The shortest pulse width in the signal equals one bit period
- **Signal separation**: Channel 0 is a reference clock, channel 1 carries data, channel 2 is noise;
only ch1 has meaningful transitions
---
## Flag
`ESPILON{s1gn4l_t4p_l41n}`
`ESPILON{s1gn4l_t4p_d3c0d3d}`