write-up: Hardware/Signal_Tap_Lain/README.md
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# Signal Tap Lain — Solution
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# Signal Tap Lain
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## Overview
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| Field | Value |
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|-------|-------|
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| Category | Hardware |
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| Difficulty | Medium-Hard |
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| Points | 500 |
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| Author | Eun0us |
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| CTF | Espilon 2026 |
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A logic analyzer capture is streamed with 3 channels. Channel 1 (ch1) contains
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UART data at 9600 baud, 8N1 format. The player must identify the protocol from
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signal timing and decode the ASCII message.
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---
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## Steps
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## Description
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1. Connect and capture the data:
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A debug probe is capturing signals from Lain's NAVI.
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Three channels are being recorded, but what protocol is in use?
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- Signal Tap: `tcp/<host>:3800`
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Capture the data, identify the protocol, and decode the message.
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Format: **ESPILON{...}**
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---
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## TL;DR
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Download a multi-channel logic analyzer CSV capture. Identify that channel 1 carries UART
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at 9600 baud by measuring the bit period. Implement UART 8N1 decoding (LSB-first) and
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extract the ASCII flag, which is repeated 3 times in the stream.
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---
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## Tools
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| Tool | Purpose |
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|------|---------|
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| `nc` | Capture the signal tap data |
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| Python 3 / numpy | Logic analysis and UART decoding |
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| `info` command | Get channel metadata from the service |
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---
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## Solution
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### Step 1 — Connect and capture
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```bash
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nc <host> 3800 > capture.csv
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```
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Wait for `--- END OF CAPTURE ---`.
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Wait for `--- END OF CAPTURE ---` then press Ctrl+C.
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1. Analyze the capture. Use `info` command for metadata:
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### Step 2 — Get metadata
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Connect again and issue:
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```text
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info
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```
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Shows 3 channels: ch0 (reference), ch1 (data), ch2 (noise).
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Output:
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1. Focus on ch1. Look for patterns:
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```
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Channels: 3
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ch0: reference clock (always HIGH)
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ch1: data line
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ch2: noise channel
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Sample rate: 1 MHz
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```
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- Idle state is HIGH (1)
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- Periodic falling edges = start bits
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- Measure time between start bits to find character period
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> 📸 `[screenshot: info command output listing the three channels]`
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1. Calculate baud rate:
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### Step 3 — Analyze channel 1
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- Bit period ≈ 104.17 μs → 9600 baud
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- Character frame = 10 bits (1 start + 8 data + 1 stop) = ~1041.67 μs
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Focus on ch1. The key observations:
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1. Decode UART 8N1:
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- Idle state is **HIGH** (logic 1) — consistent with UART
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- Periodic **falling edges** = start bits
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- Measure the time between the start bit falling edge and the next bit transition
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- Start bit: falling edge (HIGH → LOW)
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- Sample data bits at center of each bit period (1.5 × bit_period after start)
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- 8 data bits, LSB first
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- Stop bit: HIGH
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### Step 4 — Calculate baud rate
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1. Script or manually decode the ch1 data to ASCII. The message contains the flag
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repeated 3 times.
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Measure the minimum pulse width in the ch1 column:
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## Key Concepts
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```
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Bit period ≈ 104.17 μs
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Baud rate = 1 / 0.00010417 ≈ 9600 baud
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```
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- **Logic analysis**: Reading digital signals and identifying protocols from timing patterns
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- **UART 8N1**: Universal Asynchronous Receiver/Transmitter — start bit, 8 data bits LSB-first, no parity, 1 stop bit
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- **Baud rate detection**: Measuring the shortest pulse width gives the bit period → baud rate
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- **Signal separation**: In a multi-channel capture, identifying which channel carries useful data
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A 10-bit UART frame (1 start + 8 data + 1 stop) = ~1041.67 μs.
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> 📸 `[screenshot: Python script measuring bit periods from ch1 transitions]`
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### Step 5 — Decode UART 8N1
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```python
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import csv
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# Load capture
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with open("capture.csv") as f:
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reader = csv.DictReader(f)
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rows = list(reader)
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timestamps = [float(r["timestamp_us"]) for r in rows]
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ch1 = [int(r["ch1"]) for r in rows]
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BIT_PERIOD = 104.17 # microseconds at 9600 baud
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chars = []
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i = 0
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while i < len(ch1) - 1:
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# Find start bit (falling edge: HIGH → LOW)
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if ch1[i] == 1 and ch1[i+1] == 0:
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start_time = timestamps[i+1]
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# Sample 8 data bits at center of each bit period
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bits = []
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for b in range(8):
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sample_time = start_time + BIT_PERIOD * (1.5 + b)
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# Find closest sample
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j = min(range(len(timestamps)),
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key=lambda k: abs(timestamps[k] - sample_time))
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bits.append(ch1[j])
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# LSB first
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byte = int("".join(map(str, reversed(bits))), 2)
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if 32 <= byte <= 126:
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chars.append(chr(byte))
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i += int(BIT_PERIOD * 10 / (timestamps[1] - timestamps[0]))
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else:
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i += 1
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print("".join(chars))
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```
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The decoded message contains the flag repeated three times.
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> 📸 `[screenshot: decoded UART output showing the flag repeated]`
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### Key concepts
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- **Logic analysis**: Reading digital waveforms and identifying protocols from timing patterns
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- **UART 8N1**: Start bit (HIGH→LOW), 8 data bits LSB-first, no parity bit, 1 stop bit (HIGH)
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- **Baud rate detection**: The shortest pulse width in the signal equals one bit period
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- **Signal separation**: Channel 0 is a reference clock, channel 1 carries data, channel 2 is noise;
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only ch1 has meaningful transitions
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---
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## Flag
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`ESPILON{s1gn4l_t4p_l41n}`
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`ESPILON{s1gn4l_t4p_d3c0d3d}`
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